The people involved in the data processing operation are known as <span>Peopleware.</span>
Answer:
1066.67 N
Explanation:
Given that two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms.
Force × effort of arm distance= input weight × load distance
200 N * 8 m = x * 1.5 m
1600 = 1.5x
x = 1600/1.5
x = 1066.666 N
it takes 1066.67 N to lift the input weight
Explanation:
The X's have been correctly placed in the chart
A surge suppressor, which is also commonly known as a surge protector, is an important equipment that helps prevent damage to electric components from an unexpected increase of voltage. Let’s assume that you are living in a county where the effective utility voltage is between 110 to 120 volts. Assume that the accepted peak voltage should not be anything higher than 170 volts. If there is a surge and this surge reaches peak levels of 170 volts and higher, surge suppressors should jump in and prevent the peak AC voltage from going above the threshold.
People tend to confuse line conditioners and surge suppressors. While surge suppressors protect components from surges, line conditioners are built to make up for the loss of voltage from the lines. It does so by storing some power energy. This stored energy can later be modified and used when the volts drops to the desired 110 volts.
A UPS has DC battery power that provides battery backup power when the electricity goes off or when the levels of voltage drop significantly. When the electricity goes off means that the voltage is at 0 volts and it is the work of the UPS to kick its backup power in.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
