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rusak2 [61]
3 years ago
6

What is the sum of the polynomials (m+n+3)(m+n+4)

Mathematics
2 answers:
poizon [28]3 years ago
4 0
(m + n + 3)(m + n + 4)
First distribute the m in the first set of parentheses to the second set of parentheses.  Do the same process with the n and the 3.
m^2 + mn + 4m + mn + n^2 + 4n + 3m +3n + 12
Combine Like terms. Final Answer:
m^2 + n^2 + 2mn + 7m + 7n + 12
poizon [28]3 years ago
4 0

Answer:

2m+2n+7

Step-by-step explanation:

Given: Two polynomial

P_1=m+n+3

P_2=m+n+4

We need to find the sum of polynomial.

Sum=P_1+P_2

\Rightarrow (m+n+3)+(m+n+4)

write like term together  

\Rightarrow m+m+n+n+3+4

Combine the like term

\Rightarrow 2m+2n+7

Hence, The sum of two polynomial is 2m+2n+7

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Step-by-step explanation:

The way the problem is written, you could also do this:

4k + m

I am joyous to assist you anytime.

3 0
3 years ago
Solve the quadratic equation for x. what is one of the roots? 2x^2+9x-5=0
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Answer:

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Step-by-step explanation:

Hope this helps.

5 0
3 years ago
HELP ME PLEASE! Part A: If (7^2)x = 1, what is the value of x? Explain your answer. (5 points)
ArbitrLikvidat [17]

Answer:

x=1/49, x=1

Step-by-step explanation:

part a:

so if (7^2)=49, you are left with 49x=1. we have to use inverse operations to isolate the variable x. this means we have to divide by 49 on both sides since 49 is multiplied with x. so, you are left with 1/49. x=1/49.

part b:

so according to the zero property, if you raise any number to the power of 0, you get 1. therefore, we are left with 1x=1. we can simplify this to x=1, which is the answer!

i think this is what you're asking for, if i misunderstood please comment under my response!

4 0
4 years ago
What is the best choice for the equation of the line of best fit shown? Note that this estimate would be a strong prediction sin
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the second answer is 11

hope this helps.

7 0
3 years ago
What is the slope of a line that is parallel to the graph of 2x-3y=6
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Step-by-step explanation:

The formula in y-intercept form is y=2/3x-2 when converted from standard

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