Is there any more to this question? Because-5 doesn’t belong anywhere
Area = length *width
A = x²
3x² = (x+10)(x+12)
3x² = x²+10x+12x+120
3x² = x²+22x+120
3x²-3x² = x²+22x+120-3x²
0 = -2x²+22x+120
Factor to solve for x:
-2(x²-11x-60)
(x+4)(x-15)
x = -4 & x = 15 but we can't have a negative length so we eliminate 4. The length of the square is 15 cm.
Answer:
267 - 112 - 65 - 33 = $57
Step-by-step explanation:
subtract to get the answer
Answer:
d(4) = 64
Step-by-step explanation:
Using the recursive formula
d(n) = d(n - 1) + 17 with d(1) = 13, then
d(2) = d(1) + 17 = 13 + 17 = 30
d(3) = d(2) + 17 = 30 + 17 = 47
d(4) = d(3) + 17 = 47 + 17 = 64
Let's solve this by using the quadratic formula:

Note that we only use the coefficients so a=12, b=-14, and c=-6.
Plug values in the quadratic equation:

And so by evaluating those values we obtain:

Now we have two answers which are our factors one where we add another where we subtract and so:
First factor:

Second Factor:

And so your factors are

meaning that those are your roots/x-intercepts.