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Eva8 [605]
2 years ago
14

What is the slope of a line that is parallel to the graph of 2x-3y=6

Mathematics
1 answer:
Rus_ich [418]2 years ago
7 0

Answer: 2/3

Step-by-step explanation:

The formula in y-intercept form is y=2/3x-2 when converted from standard

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Please help!! The last problem!!
malfutka [58]
It should be -3, you have to plug the points into the slope formula
4 0
3 years ago
Triangle ABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C? A. 9/41 B. 40/9 C. 40
seraphim [82]
The answer is letter C which is 40/41. If you draw a triangle the sides found in the cos C is BC which is equal to 40 and the CA which is equal to 41 or the 40/41. It can not be the AB since it is in the opposite side of the cos C. 
5 0
3 years ago
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Can anyone solve these I need the steps for each number
elena-14-01-66 [18.8K]

6. Consecutive interior, k

7. Alternate exterior, m

8. No relationship, k

9. Corresponding, j

10. Alternate interior, l

11a 131, vertical angles

b 49, linear pair

c 131, corresponding angles

d 49, corresponding angles

e 131, vertical angles

f 49, vertical angles

g 49, vertical angles

h 92, linear pair

i 88, vertical angles

j 92, corresponding angles

k 88, corresponding angles

l 92, vertical angles

m 88, vertical angles

n 92, vertical angles

7 0
2 years ago
Perform the indicated operation. 3a3x(4a2bcx3)
pochemuha

We are given expression: 3a^3x(4a^2bcx^3)

3a^3x is in front of Parenthesis.

So, we need to apply multiplication operation there.

We need to multiply like terms( numbers by number and variables by variables).

First we multiply 3 * 4, it gives 12.

Now, a^3 * a^2. In order to multiply a^3 * a^2, we need to apply product rule of exponents.

According to product rule of exponents, when bases are same, we just need to add the exponents by keeping same base.

Therefore, a^3*a^2=a^{3+2}=x^5

On the same way, we can apply apply product rule of exponents on multiplication of

x and x^3.

x * x^3 = x^{1+3} = x^4.

Therefore, final answer would be

3a^3x(4a^2bcx^3)=12a^5bx^4.

7 0
3 years ago
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How do I solve for x?
Vitek1552 [10]
I guess you multiply everything times "x", the Xs cancel out, then you will have " a + b = 1x " basically the one does not make any change, so you will end with a " a + b = x "
4 0
3 years ago
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