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Westkost [7]
3 years ago
10

Joy wants to buy strawberries and raspberries to bring to a party. Strawberries cost $1.60 per pound and raspberries cost $1.75

per pound. If she only has $10 to spend on berries, which inequality represents the situation where she buys x pounds of strawberries and y pounds of raspberries?
A.1.60x+1.75y≤10
B.1.60x+1.75y≥10
C.1.75x+1.60y≤10
D.1.75x+1.60y≥10
Mathematics
1 answer:
zimovet [89]3 years ago
5 0

Answer: 1.60x + 1.75y is less than or equal to 10

Step-by-step explanation:

Since the strawberries cost $1.60 per pound, it would be x pounds times $1.60 for the total cost of strawberries. Since the raspberries cost $1.75 per pound, it would be y pounds times $1.75 for the total cost of the raspberries. The total cost of both, or 1.60x + 1.75y, must be equal to or less than 10 because she cannot spend over 10 dollars.

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Mrrafil [7]
3x-14=4x-36
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7 0
2 years ago
Solve equation. Verify answer 14=-2w
notka56 [123]

Answer:

w = -7

Step-by-step explanation:

Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other.

Divide -2 from both sides:

(14)/-2 = (-2w)/-2

(14)/-2 = w

Note that when you are dividing:

  • 1 negative & 1 positive sign will result in a negative answer
  • 2 negative sign will result in a positive
  • 2 positive sign will result in a positive

In this case:

(14)/-2 = -7

-7 is your answer for w.

~

8 0
3 years ago
A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and
goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

5 0
3 years ago
Anna is holding a party for six children. She buys cupcakes which come in boxes of four. The children eat all the cupcakes and t
Karolina [17]
Anna could have bought 3 boxes, which would serve 2 cupcakes to each child.
8 0
3 years ago
Read 2 more answers
Please include work
OLga [1]

Answer:

9.     6k + 5 and 2k - 1.

10.    5√2 .

Step-by-step explanation:

9.    Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10.  The ratio of a leg to the hypotenuse is  1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2  

= 10 √2  / 2

= 5√2 .

7 0
3 years ago
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