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Ksenya-84 [330]
3 years ago
14

Can you please help will give brainliest please

Mathematics
2 answers:
lakkis [162]3 years ago
8 0

Answer: Tyler traveled 16 blocks

Step-by-step explanation:

Brrunno [24]3 years ago
4 0
The perimeter is 18. Which would be the distance.
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Tell me the answerrr plz
AnnZ [28]
The range is from 6 to 18.
6 0
3 years ago
Which fractoin is the least 1/2 1/5 1/7 or 1/10​
torisob [31]

Answer:

1/10

Step-by-step explanation:

1/2= 50%

1/5= 20%

1/7= 15%

1/10= 10%

8 0
3 years ago
Read 2 more answers
12. If ln(2x – 2) = 2t – 2, what is the value of x?
Katyanochek1 [597]

ln(2x – 2) = 2t – 2

2x-2=e^(2t-2)

x=e^(2t-2)/2+1

8 0
3 years ago
What is 2+2-2*2/2= to
sveticcg [70]
2+2-2*2/2 divide 2/2=
2+2-2*1 multiply 2*1=
2+2-2 add 2+2=
4-2 subtract 4-2=
2
answer= 2
7 0
3 years ago
Read 2 more answers
The athlete’s salary, in thousands, for the first two years is $400 and $400(1.05). Explain how to find her salary for each of t
enyata [817]
To find the salary for the next three years, we are going to use the formula for the nth term of a geometric sequence: a_{n}=a_{1}r^{n-1}
where
a_{n} is the nth term of the sequence 
a_{1} is the first term in the sequence 
r is the common ratio 
n is the position of the term in the sequence 

To check if the values $400 and 400(1.05) for a geometric sequence, we are going to find their common ratio. To find the common ratio, we are going to use the formula r= \frac{a_{n} }{a_{n-1}}
where 
a_{n} is the current term in the sequence 
a_{n-1} is the previous term in the sequence

We can infer from our values, that the current term of the sequence is 400(1.5), so a_{n-1}=400(1.5). That leaves 400 as the previous term, so a_{n-1}=400. Lets replace those values in our formula to find r:
r= \frac{a_{n} }{a_{n-1}}
r= \frac{400(1.05)}{400}
r=1.05

Now that we have our common ratio, we can replace it in our formula for the nth term to find the athlete's salary for each of the next three years. Notice that the first term of our sequence is $400, so a_{1}=400
a_{n}=a_{1}r^{n-1}
a_{n}=400(1.05)^{n-1}
a_{3}=400(1.05)^{3-1}
a_{3}=400(1.05)^{2}
a_{3}=441

a_{4}=400(1.05)^{4-1}
a_{4}=400(1.05)^{3}
a_{4}=463.05

a_{5}=400(1.05)^{5-4}
a_{5}=400(1.05)^4
a_{5}=486.2025

We can conclude that the athlete's salary for each of the next three years is: $441,$463.05,486.2025 respectively. Also, those vales for a geometric sequence because they share a common ratio, (1.05).
6 0
3 years ago
Read 2 more answers
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