2 years ago

Using the point-slope equation, find the equation containing (-2, -4) and slope m = -1

Mathematics

1 answer:

Kipish [7]2 years ago

3 0

Y=mx + b

(y - y^1)/ (x- x^1)= m
m=-1
y-(-4)/ x-(-2)= -1

(y+4)/ (x+2)= -1

y+4= -1(x+2)

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Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

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The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

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$\frac{5}{13} = \frac{c}{a}$

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Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

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$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

The equation of the elipse is:

$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

A similar problem is given at brainly.com/question/21405803

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