Question

Eight times the first of three consecutive odd integers is 4 less than thrice the sum of second and third. The second integer is

Answer 1

Answer:

9

Step-by-step explanation:

first integer = x

second integer = x+2

third integer = x+4

8x=3(x+2+x+4)-4

8x=3(2x+6)-4

8x=6x+18-4

8x=6x+14

2x=14

x=7

second integer=7+2=9