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3 years ago

Which units are most appropriate for measuring the length of an edge of a postage stamp?

Mathematics

1 answer:

Neko [114]3 years ago

3 0

Answer:

A. Centimeters

Step-by-step explanation:

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If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (fºg)(x)?

RUDIKE [14]

Answer:

(-∞, ∞)

Step-by-step explanation:

Given,

$f(x)=x^2-1 \ and\ g(x)=2x-3$

Then (fºg)(x) would be ,

$(2x-3)^2-1\\4x^2-12x+9-1\\4x^2-12x+8$

Since this is a polynomial, we know domain of a polynomial is all real number.

Therefore the domain of this (fºg)(x) is (-∞, ∞).

5 0

3 years ago

Dave is selling hand made masks for $8 per mask. He has already earned $120. Dave wants to make a total profit of more than $400

andrey2020 [161]

Answer:

I dont no

Step-by-step explanation:

4 0

3 years ago

Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin

katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula $A=P(1+\frac{r}{n})^{nt}$

In this formula A = amount after time t

P = principal amount

r = rate of interest

n = number of times interest gets compounded in a year

t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year $A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 15000(1+.06)^{1}$

$= 15000(1.06)$ = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

$A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 20900(1+.06)^{1}$

$= 20900(1.06)=22154$

So the final amount will be $22154.

3 0

3 years ago

Joe runs one lap around a track in 80 seconds. Joe and Jim start at the same point and run the track in opposite directions. The

inysia [295]

Joe runs one lap around a track in 80 seconds. Joe and Jim meet after 30 seconds.We know how long does it take for Joe to run one lap, so we can calculate what distance he runs in 30 seconds:
He runs half lap for 40 seconds. He runs quarter lap for 20 minutes and he runs 1/8 lap for ten minutes. So for 30 seconds he runs 3 * 1/8 lap=3/8 lap.
Because Jim runs in opposite direction this means that he will meat with Joe at 1-3/8=5/8 lap. So, Jim runs 5/8 lap for 30 seconds.
1/8 lap Jim runs for 30/5=6 seconds, so Jim needs 8*6=48 seconds to run the lap.
After 30 seconds Joe has run e runs

6 0

3 years ago

Round 5,600,679 to the nearest thousand

vampirchik [111]

The answer is 5,601,000

4 0

3 years ago