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malfutka [58]
3 years ago
10

Distribute: 4x(y + 7)

Mathematics
2 answers:
Georgia [21]3 years ago
7 0

Distribute. Multiply 4x to all terms within the parenthesis.

4x(y) = 4xy

4x(7) = 28x

4xy + 28x is your answer

hope this helps

kupik [55]3 years ago
6 0

To distribute in the expression 4x(y + 7), we need to know what the word distribute means. In mathematics, the distributive property is the property that says a(b + c) = a(b) + a(c). Since the question is asking us to distribute, this is what the question is asking us to do, just with different numbers. The expression becomes:

4x(y) + 4x(7)

Simplifying, we get our answer of:

4xy + 28x

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3 years ago
Read 2 more answers
A.) 170<br> B.) 300<br> C.)280<br> D.)155<br> Please help me
pav-90 [236]

Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

195 + 105 = arcEHF so

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6 0
3 years ago
What is the slope of the line that is perpendicular to the line that passes through (-2, 7) and (4, 9)? Type a numerical answer
kodGreya [7K]

Answer:

Therefore m_{2} = -3.

Step-by-step explanation:

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ii) to find the slope of the line passing through two points (x_{1}, y_{1}) and (x_{2},y_{2}) we use the formula m = \dfrac{y_{2} - y_{1} }{x_{2}  - x_{1} }. Therefore we can say that  m_{1} = \dfrac{9 - 7}{4 - (-2)} = \dfrac{1}{3}.

iii) let us say the slope of the perpendicular line to the line  passing through (-2,7) and (4,9) is m_{2}

iv) from the formula for the slopes of a line and the line perpendicular to it which is given by m_{1} × m_{2} = -1, therefore m_{2} = -1 ÷  m_{1} = -3. Therefore m_{2} = -3

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