The required value of mean and variance is 203 and 3942 respectively.
Hence option B is correct.
The sample includes the following claims: 192, 113, 200, 287, and 225.
<h3>What is Statistic?</h3>
The statistic is the study of mathematics which deal with relations between comprehensive data.
Mean(x) = 192+113+200+287+225/5
x = 203
variance =
=summation of squared value/n^2−1
=15769/25−1
=15769/24
=3942
Thus, the required value of mean and variance is 203 and 3942 respectively.
Learn more about Statistics here:
brainly.com/question/23091366
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Your answer will most likely be A
Answer:
i think a
Step-by-step explanation:
Answer: 4(−a+1)(a−1)
Step-by-step explanation:
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
