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const2013 [10]
2 years ago
5

Make t the subject of the formula: S = at + bt

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
8 0
To make t the subject is basically isolating t

S = at + bt
We see on the right side that t is common, so we factor it out.

S = t(a + b)
Divide by (a+b) to isolate t

\frac{S}{a + b} =  \frac{t(a+b)}{(a+b)}
a + b and a + b cancels out
We are left with the answer:
t = \frac{S}{a+b}
goldfiish [28.3K]2 years ago
6 0
S = at + bt \\
t(a+b)=S\\
t=\dfrac{S}{a+b}
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Is lb bigger or smaller than oz
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2 years ago
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84.7g of sugar is needed to make 11 cakes. How much sugar is needed for 5 cakes
Yuri [45]

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4 0
3 years ago
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Choose the graph that matches the following system of equations: 2x + y = −1 3x + 2y = −6
Karolina [17]
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Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.

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4 0
3 years ago
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Evaluate the surface integral. s x ds, s is the triangular region with vertices (1, 0, 0), (0, −2, 0), and (0, 0, 12).
aniked [119]
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\mathbf r(s,t)=(1-s)(0,0,12)+s\bigg((1-t)(1,0,0)+t(0,-2,0)\bigg)
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where (s,t)\in(0,1)\times(0,1). We have

\|\mathbf r_s\times\mathbf r_t\|=\|(1-t,-2t,-12)\times(-s,-2s,0)\|=2\sqrt{181}s

The surface integral is then

\displaystyle\iint_Sx\,\mathrm dS=2\sqrt{181}\int_{s=0}^{s=1}\int_{t=0}^{t=1}s(s-st)\,\mathrm dt\,\mathrm ds
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3 years ago
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