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harkovskaia [24]
3 years ago
8

I need help and only even numbers ​

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

12.

-1.9 , -1.8, -1.7

13.

Points in Quadrant IV have a positive x, and a negative y.

14.

The point (2,9) is reflected over the y-axis, which means the number in x has it's sign flipped.

(-2 , 9) is your answer

15.

In between -7 & -4 is <em>-6, -5</em>

b. -6 is your answer.

16.

Remember that Quadrant II has a negative x, and a positive y. This means that b. (-2, 5) is your answer.

17.

You are reflecting over the y-axis, so you are changing the sign of the x value.

(-3, 5) reflected over the y-axis is a. (3 , 5)

~

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If AACD ~ AABE, find the value of x.
Anastaziya [24]

9514 1404 393

Answer:

  x = 16

Step-by-step explanation:

Corresponding sides are proportional.

  BE/CD = AE/AD

  20/(3x+8) = (x-1)/(x-1+27)

  20(x+26) = (3x+8)(x -1)

In standard form, this is ...

  3x^2 -15x -528 = 0

  x^2 -5x -176 = 0 . . . . . . divide by 3

  (x -16)(x +11) = 0 . . . . . . . factor

  x = 16

__

This is the positive value that makes the product zero. x=-11 will also make the product 0, but gives negative segment lengths in the geometry. It is an extraneous solution.

4 0
3 years ago
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

<em>Let p = </em><u><em>proportion of the students who are in favor of Mike.</em></u>

So, Null Hypothesis, H_0 : p \leq 50%      {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, H_A : p > 50%      {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students body in favor of Mike = \frac{55}{100} = 0.55

           n = sample of students taken = 100

So, <em><u>test statistics</u></em>  =   \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

                               =  1.01

The value of z test statistics is 1.01.

<em>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</em>

<em>Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

4 0
3 years ago
each Saturday morning Janie works 5 hours and earns $35.75. How much does Janie earn for each hour she works?
bulgar [2K]

Answer:

$7.15

Step-by-step explanation:

You would get this by dividing $35.75 by 5.

8 0
3 years ago
3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters
Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values.                       a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___  ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_<u>4</u>_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with  3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_<u>4</u>_ <u>_3_</u> ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_<u>4</u>_ _<u>3</u>_ _<u>2</u>_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

8 0
3 years ago
I am thinking of a number.
Step2247 [10]

Step-by-step explanation:

Let the number Noah is thinking of be x,

=> x - 19 * 4 = 16

=> x - 19 = 16/4

=> x = 16/4 + 19

=> x = 4 + 19

=> x = 23

If my answer helped , please mark me as brainliest,

Thank you

4 0
3 years ago
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