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3 years ago

A triangle that contains angles of 27°, 90°, and 63° is a(n) _______ triangle brainly

Mathematics

1 answer:

Whitepunk [10]3 years ago

5 0

Right triangle because of the 90. Every triangle having an angle of 90 degrees is a right triangle.

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Find the mean of 100

goldfiish [28.3K]

Answer:

100.

Step-by-step explanation:

100 + 0 = 100

100 ÷ 1 = 100

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2 years ago

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Yay! tysm guys for helping me on this test! i got a 85! :)

irakobra [83]

Answer:

Proud of you!! <3 :)

Step-by-step explanation:

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2 years ago

In a standard deck of cards there are 13 spades, 13 clubs, 13 hearts, and 13 diamonds. The spades and the clubs are black and th

Usimov [2.4K]

A 1/8.
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3 years ago

I don't understand this question at all please help if you do

lorasvet [3.4K]

Answer:

Answer is $\frac{4}{3}$

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

$-x^2+2x=y,y=0$

$-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2$

$\int\limits^2_0 {-x^2+2x} \, dx$

Integrate.

$\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3$

Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

Proof Check your interval of x.

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2 years ago

Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is n = 4225

<u>verification</u>:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

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3 years ago