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Tju [1.3M]
2 years ago
11

When a number is decreased by 10 % of​ itself, the result is 153. What is the​ number?

Mathematics
1 answer:
Olin [163]2 years ago
3 0

170 would be your answer.

Have a good day!

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Find the value of sin30+tan^(2)60+sec^(2)45​
xenn [34]

Answer:

Step-by-step explanation:

sin 30+tan²(60)+sec²(45)

=1/2+ (√3)^2+(√2)²

=1/2+3+2

=5 1/2

=5.5

3 0
2 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
2 years ago
(6 x 10^2) ÷ (3x 10^-5)
RideAnS [48]
The answer is 20000000
4 0
3 years ago
If y is directly proportional to x and when y = 35, x = 140, what is the value of x when y = 70?
levacccp [35]

Answer: 280 = x


Step-by-step explanation: Okay you are using this equation! y = kx But you must rearrange it!

When rearranged you get y/x = k

Plug in x and y!

y/x = k

35/140 = k

0.25 = k

Now find the value of x.

You use this formula now, y/k = x

Plug in k from the last problem and y = 70

y/k = x

70/0.25 = x

280 = x



6 0
3 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

16 + 25 = 41

<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

n² + n² + 2(n)(1) + 1² = 41

2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
2 years ago
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