1. 10
2(3 + 2)
2(5)
10
2. $631
59 + 13(44)
59 + 572
631
3. a number decreased by 4
Answer:
0
Step-by-step explanation:
i think im not sure the way this question is written doesn't make a lot of sense
Give me a question i can answer. i might could help.
You would have to first times .03 times 10 then take that times 30,000 which should equal 900
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>