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kifflom [539]
4 years ago
12

A man drove x miles per hour for 3e hours and (2x-60) miles per hour for the next 4.75 hours. Express the total distance he trav

eled in terms of x
Mathematics
1 answer:
avanturin [10]4 years ago
6 0

Answer:

A man drove x miles per hour for 3 hours and (2x-60) miles per hour for the next 4.75 hours.Express the total distance traveled in terms of x.

Total distance covered by the man in terms of 'x' = (12.5x-285)miles

Step-by-step explanation:

Given:

Speed of  a man = 'x' miles/hour

Time taken = 3 hour

So, distance = product of speed and time.

Distance covered in term of 'x' =(d_1=3x)

Now,

Speed = (2x-60) miles/hour

Time taken= 4.75 hours

Distance (d_2)  = (2x-60)\times 4.75

                      = (2x\times 4.75) -(60\times 4.75)

                      = (9.5x - 285) miles

Total distance covered by the man = Summation of  d_1 and d_2

                                                           = (9.5x-285+3x)

                                                           = (12.5x-285) miles

So the total distance covered by the man in terms of 'x' = (12.5x-285) miles.

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What Value of X satisfies this equation?
Salsk061 [2.6K]

Answer:

x=0

Step-by-step explanation:

4 ( 2.5) ^x = 4

Divide each side by 4

4/4 ( 2.5) ^x = 4/4

( 2.5) ^x = 1

Take the log of each side

log  ( 2.5) ^x =  log (1)

x log ( 2.5) = log 1

x log (2.5) = 0

Divide each side by log (2.5)

x = 0

5 0
3 years ago
I don’t get this...!!!
notka56 [123]
Ray CB, because it will include point A in the ray
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3 0
4 years ago
In a regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample points in the sample space
posledela

Answer: a.) 40320

b.) 336

Step-by-step explanation:

since we have 8 possible positions, with 8 different candidates, then there are 8 possible ways of arranging the first position, 7 possible ways of arranging the Second position, 6 ways of arranging the 3rd position, 5 possible ways od arranging the 4th position, 4 possible ways of arranging the 5th position, 3 possible ways of arranging the 6th position, 2 possible ways of arranging the 7th position and just one way of arranging the 8th position since we have only one person left.

Hence, the Number of possible sample space for different 8 positions is by multiplying all the number of ways we have in our sample space which becomes:

8*7*6*5*4*3*2*1 = 40320.

b.) By the sample space we have, since we've been asked ti arrange for only the firat 3 positions, then we multiply just for the first 3ways of choosing the positions, this becomes:

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5 0
3 years ago
A cake is removed from a 310°F oven and placed on a cooling rack in a 72°F room. After 30 minutes the cake's temperature is 220°
Fynjy0 [20]

Answer:

The time is 135 min.

Step-by-step explanation:

For this situation we are going to use Newton's Law of Cooling.

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium and is given by

T(t)=C+(T_0-C)e^{kt}

where,

C = surrounding temp

T(t) = temp at any given time

t = time

T_0 = initial temp of the heated object

k = constant

From the information given we know that:

  • Initial temp of the cake is 310 °F.
  • The surrounding temp is 72 °F.
  • After 30 minutes the cake's temperature is 220 °F.

We want to find the time, in minutes, since the cake's removal from the oven, at which its temperature will be 100°F.

To do this, first, we need to find the value of k.

Using the information given,

220=72+(310-72)e^{k\cdot 30}\\\\72+238e^{k30}=220\\\\238e^{k30}=148\\\\e^{k30}=\frac{74}{119}\\\\\ln \left(e^{k\cdot \:30}\right)=\ln \left(\frac{74}{119}\right)\\\\k\cdot \:30=\ln \left(\frac{74}{119}\right)\\\\k=\frac{\ln \left(\frac{74}{119}\right)}{30}

T(t)=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}

Next, we find the time at which the cake's temperature will be 100°F.

100=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}\\72+238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=100\\238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=28\\e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=\frac{2}{17}\\\ln \left(e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}\right)=\ln \left(\frac{2}{17}\right)\\\frac{\ln \left(\frac{74}{119}\right)}{30}t=\ln \left(\frac{2}{17}\right)\\t=\frac{30\ln \left(\frac{2}{17}\right)}{\ln \left(\frac{74}{119}\right)}\approx 135.1

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nirvana33 [79]

Answer:

$2768.83

Step-by-step explanation:

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(92+92+48)x 2=464 in

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898/12= 74.8

74.8 x 37= $2768.83

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5 0
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