1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Amanda [17]
3 years ago
11

The graphs of f(x) and g(x) are shown below:

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0
<h2>Answer:</h2>

Option: C is the correct answer.

            C.)   x = −3.8, 3

<h2>Step-by-step explanation:</h2>

The function f(x) is given by:

           f(x)=x^2-x-12

and the function g(x) is given by:

            g(x)=-1.8x-0.6

Now, we are asked to find the solution of the equation:

        f(x)=g(x)

i.e. we have to find the value of x such that both the functions are equal i.e.

x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

ax^2+bx+c=0

is given by:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=5,\ b=4\ and\ c=-57

Hence, the solution is given by:

x=\dfrac{-4\pm \sqrt{4^2-4\times 5\times (-57)}}{2\times 5}\\\\i.e.\\\\x=\dfrac{-4\pm \sqrt{16+1140}}{10}\\\\i.e.\\\\x=-3.8\ and\ x=3

You might be interested in
Factor 2xz - 3yz + 8x - 12y completely. If the polynomial is not factorable, write prime. SHOW YOUR WORK FOR FULL CREDIT!
Mars2501 [29]
X57 I think no just doing this for points so made a random number lol
3 0
3 years ago
Read 2 more answers
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
~I ~ need ~ help ~ once ~ again~
ruslelena [56]
A. 12pi meters.

Circumference = pi x diameter (pi x 12 = 12pi)
Diameter = 2 x radius (2 x 6 = 12)

8 0
3 years ago
How do I find the area of a triangle
Ratling [72]

Answer:

Area of triangle = ½ × base × height

Step-by-step explanation:

(A = ½ × b × h)

This formula is mainly used to find the area of the triangle.

4 0
3 years ago
Read 2 more answers
you're 495 miles from home and you are driving toward home at an average of 45mph. How long will it take to drive home if you ma
LenaWriter [7]

11 hours because I did the math

7 0
3 years ago
Other questions:
  • Which of the following illustrates the truth value of the given conditional statement?
    11·1 answer
  • If you can run at 10mail an hour then how far can you get in 10 days and you take no brakes
    8·2 answers
  • 6/36 in simplest form
    5·2 answers
  • what wpuld be the area of an actual pool be of the scale from the drawing is 3:1000? 15 cm7.5 will mark brainest
    12·1 answer
  • Hey, can you guys please help me get the answer. And explain it to me so i know? Thank you.
    5·2 answers
  • What is the volume of the oblique cylinder rounded to the nearest cm^3?
    14·1 answer
  • How do you graph x ≤ 5 on a number line? pls help!
    8·1 answer
  • Pretty easy math question<br><br>-4/7 x (-5)<br><br>make sure final answer is in simplest form.
    11·1 answer
  • Can someone please help me please
    7·1 answer
  • Work out the missing value in the estimation below.<br> 237 + 462 ~ 200 +
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!