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e-lub [12.9K]
3 years ago
7

What is the purpose of the Occupational Safety and Health Act?

Computers and Technology
2 answers:
cupoosta [38]3 years ago
4 0

Answer:to govern job related health and safety

Explanation:

APEC

NikAS [45]3 years ago
3 0

Answer:

The purpose of this act was to reduce workplace hazards and implement more safety and health programs for both employers and their employees.  

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A program is required to three (3) numbers. calculate and print their total
podryga [215]

A program that is required to three (3) numbers. calculate and print their total is given below:

<h3>The Program</h3>

import java.util.Scanner;

public class SumAndAverage {

public static void main(String[ ] args) {

System.out.println("Enter three numbers - ");

// Accepting and finding sum of numbers.

int sum = 0;

Scanner sc = new Scanner(System.in);

for (int i = 0; i < 3; i++)

sum += sc.nextInt( );

// Printing sum and average.

System.out.println("Sum - " + sum);

System.out.println("Average - " + (sum / 3f));

}

}

The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total


Read more about programming here:

brainly.com/question/23275071

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5 0
2 years ago
Consider a binary search tree where each tree node v has a field v.sum which stores the sum of all the keys in the subtree roote
AVprozaik [17]

Answer:

Each time you insert a new node, call the function to adjust the sum.

This method has to be called each time we insert new node to the tree since the sum at all the

parent nodes from the newly inserted node changes when we insert the node.

// toSumTree method will convert the tree into sum tree.

int toSumTree(struct node *node)

{

if(node == NULL)

return 0;

// Store the old value

int old_val = node->data;

// Recursively call for left and right subtrees and store the sum as new value of this node

node->data = toSumTree(node->left) + toSumTree(node->right);

// Return the sum of values of nodes in left and right subtrees and

// old_value of this node

return node->data + old_val;

}

This has the complexity of O(n).

Explanation:

6 0
3 years ago
I know that this will be taken down for not being a real question but is anyone else not able to search for anything? I can type
Schach [20]

Answer:

Sameee

Explanation:

6 0
3 years ago
g Create a program that reads a list of states from an input file, puts them in order, and displays the sorted list to the user.
mixas84 [53]

Answer:

Check the explanation

Explanation:

# Step 1

the first thing to execute will be......

f = open("states.txt")

# Step 2

the second step is......

states = []

for line in f:

   states.append(line.strip())

# Step 3:

the third step is to......

for state in sorted(states):

   print(state)

f.close()

3 0
3 years ago
Write a program that uses an STL List of integers. a. The program will insert two integers, 5 and 6, at the end of the list. Nex
poizon [28]

Answer:

answer:

#include <iostream>

#include<list>

using namespace std;

bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;

l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";

/*Display the list*/

cout<<endl; return 0;

}

5 0
3 years ago
Read 2 more answers
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