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Leona [35]
3 years ago
13

Simplify log (x2-y2)- log (x-y)=

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Using the law of logarithm.  LogA - LogB =  Log(A/B)

log(x²-y²) - log(x-y) = log((x²-y²)/(x-y))

Note by difference of two squares, (x²-y²) = (x-y)(x+y)

Simplifying (x²-y²)/(x-y) = (x-y)(x+y)/(x-y) = (x+y)

Therefore log(x²-y²) - log(x-y) = log((x²-y²)/(x-y)) = log((x-y)(x+y)/(x-y)) = log(x+y)
jok3333 [9.3K]3 years ago
3 0
<span>Remember:
log A - log B=log (A/B)
(a</span>²-b²)=(a+b)(a-b).

Therefore

log (x²-y²)-log(x-y)=log[(x²-y²)/(x-y)]= log[(x+y)(x-y)  / (x-y)]=log (x+y)

Answer: <span>log (x²-y²)-log(x-y)=<span>log (x+y)
</span></span>
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What is the scientific notation of each number 6908100000
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Answer:

6.9081 x 10^{9}

Step-by-step explanation:

7 0
3 years ago
How do I solve 3/4 =60% over 100
zepelin [54]
3/4 is 75% so the answer is 75% out of 100

Hope that helps!:)
5 0
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If an object weighs 120 pounds on earth how much will it way on mars
butalik [34]
The surface gravity of Mars is 3.7 m/s².  On Earth it is 9.8 m/s².  3.7/9.8 = 38%.

So 38% of 120 lbs is 45 pounds.
 
8 0
3 years ago
Find the horizontal asymptote off of x equals quantity 3 x squared plus 3x plus 6 end quantity over quantity x squared plus 1.
vaieri [72.5K]

Answer:

y = 3

Step-by-step explanation:

y = (3x² + 3x + 6) / (x² + 1)

The power of the numerator and denominator are equal, so as x approaches infinity, y approaches the ratio of the leading coefficients.

y = 3/1

3 0
3 years ago
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
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