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Elina [12.6K]
1 year ago
7

the eastern alberta DC transmission like is a project that began construction in 2012. It includes a 500km, 500kv power line fro

m the brooks area to the edmonton area. (the V stands for volts, and SI unit for the electrical potential)
Mathematics
1 answer:
Zielflug [23.3K]1 year ago
6 0

The number of the required towers based on the information given is 3334.

<h3 /><h3>How to calculate the number?</h3>

From the information given, it should be noted that the length of power line is 500km

The towers supporting the line are 1.5hm apart. It should be be noted that 1km = 10hm. Therefore, the require towers will be:

= (500 × 10)/1.5

= 3334

Learn more about towers on:

brainly.com/question/10717351

#SPJ1

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Six - two times twelve plus five
fomenos

Answer:

Ok, so the equation would be 6-2*12+5. The answer to that is -13.

Step-by-Step Explanation:

You would use PEMDAS. First, you multiply 2 and 12 and that's 24. Now your equation is 6-24+5. Then you subtract 6 and 24 and that's -18. Now your equation is -18+5, and the answer to that equation is -13. I hope this helps you!!

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2 years ago
The mean of six numbers is 41. If one number is removed, the mean of the five numbers is 46. Find the unknown number.
klasskru [66]
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In the 1st case n/6 = 41 ==> n =246

in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230

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2 years ago
Solve using substitution<br><br> y=1/2x<br> x+4y=18
Aleks [24]

Answer:

The solution set is (6,3)

Step-by-step explanation:

Begin by multiplying equation 1 by 2. You'll see why in a moment

2y = 2*(1/2) x

2y = x

Substitute this value into equation 2.

2y + 4y = 18                  Combine like terms on the left

6y = 18                          Divide both sides by 6

6y/6 = 18/6                    Do the division

y = 3

To solve for x just use the top equation

y = 1/2x

3 = 1/2x                          Multiply by 2

3*2 = x

x = 6


7 0
3 years ago
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