Answer:
18.84
Step-by-step explanation:
sorry if i get the wrong answer i literlly learn this but i complety forget it
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
the sine function is a many-to-one function and therefore has no inverse function.
However if the domain is restricted to -90° ≤ x ≤ 90°
Then the function is one-to-one for this domain
Thus, 
x is defined as the angle such that - π/2 ≤ x ≤ π/2
5π/6 is therefore outwith the domain
After 2 weeks:
15+3(2)=15+6= $21
After 5 weeks:
15+3(5)=15+15= $30
After 10 weeks:
15+3(10)=15+30= $45
Hope this helps
