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sleet_krkn [62]
3 years ago
13

What is an equivalent expression for 3a + 5 ?​

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

Equivalent  expression:

6a + 10

or

9a + 15

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If a person is born every 5 seconds and a person dies every 12 seconds, then how many seconds does it take for the population to
harina [27]

Solution:

As per the problem

A person is born every 5 seconds and a person dies every 12 seconds.

Here the LCD of 5 and 12 is 60.

The number of person born in 60 seconds=\frac{60}{5}=12\\

The Number of person died in 12 seconds=\frac{60}{12}=5

Hence Population increase in 60 seconds is=12-5=7\\

Hence time required to increase the population by one =\frac{60}{7} \ \ seconds\\


5 0
3 years ago
Solve for X, 132 is an exterior angle. Show work please!
Darina [25.2K]

Answer:

105/9

Step-by-step explanation:

180 - 132 = 48 degrees

180 - 48 - 45

= 180 - 93

= 87 degrees

<2 = 180 - 87

= 93 degrees

=> 9x - 12 = 93

=> 9x = 105

=> x = 105/9

6 0
2 years ago
Read 2 more answers
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
3 years ago
GIVING OUT BRAINLIEST IF YOU ANSWER!!!
Elza [17]

Answer:

a

Step-by-step explanation:

3 0
2 years ago
If anyone needs something to talk about or just needs somebody to talk too, You can comment and I'll reply as soon as possible.
vladimir2022 [97]

Answer:

<u>okurrrrr</u>

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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