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Daniel [21]
3 years ago
5

PLZ HELP!!!!!! It’s due by today .. I will make you the brainliest

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer:

draw a line like this / through zero than draw another line like this \ through zero

Step-by-step explanation:

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Please help me solve this! I’ve been stuck for ages! Thankyou
polet [3.4K]

Answer:

y = sin(x- pi/2)

Step-by-step explanation:

Please see the attached image to see your graphs.

By simple inspection we can see that the sine is shifted pi/2 to the right.

We know this because sines are periodic functions with a period T = 2*pi

We can also see that the maximum point of the graph (y = 1) got shifted by a fourth of the period.

And finally, since we want to shift the graph to the right, we need to substract from the argument of the sine term.

7 0
3 years ago
A savings account earns 4.62% annual interest, compounded continuously. After approximately how many years will a principal of $
Fantom [35]
Solve for "years" (t)

A=P e^(rt)

A=1000
P=500
e=e
r=0.0462

Solve for t: use natural logarithms

(0.0462)t=in 2

t=15 years

4 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppp plsssss​
diamong [38]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
How do you factor 35x^2+26-16? Show work please.
Sedbober [7]

well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.

35 = 5*7

16 = 2*2*2*2

and the rest is just a mix and match.

what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26?  well, without further adieu.


we can try 5*2*2  + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.

another can be 5*2*7  and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.

5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!

so then,


\bf 35x^2+26x-16\implies (5x-\stackrel{\stackrel{2}{\downarrow }}{2})(7x+\stackrel{\stackrel{2\cdot 2\cdot 2}{\downarrow }}{8})

3 0
4 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
harkovskaia [24]

Answer:

○\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]

Step-by-step explanation:

You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of \displaystyle -\frac{\sqrt{3}}{2},which gives you \displaystyle -\frac{2\sqrt{3}}{3}.

Extended Information

\displaystyle y-coordinate → sin\:θ \\ x-coordinate → cos\:θ

\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}

I am joyous to assist you anytime.

5 0
4 years ago
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