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bekas [8.4K]
3 years ago
10

HELP PLEASE!! IS A TEST

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

x=2 y 1

Step-by-step explanation:

4×2+3×1=11

8+3=11

3×2-2×1=4

6-2=4

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(3 + 2i) - (5 -7i) Write answer in standard form a +bi
Bess [88]

(3 + 2i) - (5 - 7i)

Distribute the - sign

3 + 2i - 5 + 7i

Combine like terms

-2 + 9i

4 0
3 years ago
Measure the size of the angle between the 9cm and 6cm triangular sides to the nearest degree
Irina-Kira [14]

Answer:

This is a protractor question if you dont have one then try these on a calculator.

when angle is between two lines we need see where the hypotenuse is in the diagram and where is the adjacent.

And whether the triangle is right angle or not.

Try these

shift sin -1  x sin 9/6 (for opp/hyp)

shift sin -1  (9/6)   (for opp/hyp)

shift sin -1 x sin 6/9 (for opp/hyp)

shift sin -1 (6/9) (for opp/hyp)

shift cos -1 x cos 9/6 (for adj/hyp)

shift cos -1 (9/6) (for adj/hyp)

shift cos -1 x cos (6/9) (for adj/hyp)

shift cos -1 (6/9) (for adj/hyp)

shift tan -1 x tan (9/6) ( for opp/adj)

and so on....

Step-by-step explanation:

4 0
3 years ago
Find the area to the right of the z-score 1.39 and to the left of the z-score 1.53 under the standard normal curve.1.2 1.3 1.4 0
svetoff [14.1K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is  P( 1.39 <  z <  1.53 ) = 0.0193

Step-by-step explanation:

From the question we are told to obtain the area to the of the z-score 1.39 and to the left of the z-score 1.53, this is mathematically represented as

        P( 1.39 <  z <  1.53 ) =  P( z <  1.53 ) - P( z <  1.39 )

From the z table on the question the area under the normal curve to the left corresponding to 1.53 and  1.39  is

       P( z <  1.53 )  = 0.9370

and

      P( z <  1.39 )  = 0.9177

So

     P( 1.39 <  z <  1.53 ) = 0.9370 - 0.9177

=>  P( 1.39 <  z <  1.53 ) = 0.0193

6 0
3 years ago
A function f is periodic of period of period 5. If f(3)=10,f(0)=13, and f(-5)=31 then find f(13)
ollegr [7]
If f(x) is some function with period T, then f(x) = f(x+T) for all x in the domain.

In this case, T = 5 is the period so

f(x) = f(x+5)
f(3) = 10
f(3) = f(3+5) = f(8) = 10
f(8) = f(8+5) = f(13) = 10

Therefore, f(13) = 10

The final answer is 10
3 0
2 years ago
Given f z please help
Softa [21]

Answer:

z = -11, z = -2

Step-by-step explanation:

Given that, (f(z)=\sqrt{z+27} -z) and (f(z)=7), set up an equation that puts the first value of (f(z)) equal to the other given value of the function.

f(z)=\sqrt{z+27}-z=7

Use inverse operations to solve,

\sqrt{z+27}-z=7\\\\\sqrt{z-27}=7+z\\\\z+27 = (7+z)^2\\\\z + 27 = 49+14z+z^2\\ -(27+z)\\\\0 = z^2+13z+22

Factor,

0=(z+11)(z+2)

Solve using the zero product property, the zero product property states that any number times zero equals zero;

z=-11,z=-2

3 0
2 years ago
Read 2 more answers
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