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MissTica
4 years ago
5

Which reading is expected from a thermometer near Earth’s surface during a period of freezing rain?

Chemistry
1 answer:
NNADVOKAT [17]4 years ago
7 0
I assume this is a multiple choice question by the way it is worded, but out of all the choices I would assume it would be the temperature above freezing point, but not extremely high.
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Any solution to the problem
Sophie [7]

Answer:

the first one

Explanation:

7 0
3 years ago
The formula for one molecule of sucrose is shown below.
valina [46]

Answer:

45

Explanation:

There are 12 Carbons

There are 22 Hydrogens

There are 11 Oxygens.

I think the answer is either 0 or 45. But the wording is very sloppy. It is not really atoms that are present. There are ions.

Go with 45 but hold your nose when writing your answer.

6 0
3 years ago
Across<br> 1. the alkali metal in Period 4
lana [24]
The answer ispotassium (K)
3 0
4 years ago
A Sattelite is a (n)
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6 0
4 years ago
Find the solubility of agi in 2.5 m nh3 [ksp of agi = 8.3 × 10−17; kf of ag(nh3)2+ = 1.7 × 107].
vovangra [49]
When the first reaction equation is:

AgI(S) ↔ Ag+(Aq)  +  I-(Aq)

So, the Ksp expression = [Ag+][I-]

∴Ksp = [Ag+][I-] = 8.3 x 10^-17

Then the second reaction equation is:

 Ag+(aq)  + 2NH3(aq) ↔  Ag(NH3)2+  

So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2

∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7

by combining the two equations and solve for Ag+:

and by using ICE table:

               AgI(aq) + 2NH3  ↔  Ag(NH3)2+  + I-
initial                        2.5                    0            0 

change                    -2X                    +X             +X

Equ                     (2.5-2X)                   X               X

so K = [Ag(NH3)2+] [I-] / [NH3]^2

Kf * Ksp = X^2 / (2.5-2X)

8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X

∴ X = 5.9 x 10^-5 

∴ the solubility of AgI = X = 5.9 x 10^-5 M

4 0
3 years ago
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