If I have an unknown quantity of gas at a pressure of 204.83 kPa, a volume of 27.88 liters, and a temperature of 8.76°C , how ma
2 answers:
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Answer: The initial partial pressures of and
is 139.4 torr.
Explanation:
The equilibrium reaction is
initially conc. p p 0
At eqm. p-2x p-x 2x
Given:
The expression for equilibrium constant is :
= 2x =115 torr
= (p-2x) = p-115 torr
= (p-x)= p-57.5 torr
Now put all the given values in this expression, we get
Therefore, the initial partial pressures of and
is 139.4 torr.