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sertanlavr [38]
2 years ago
13

If I have an unknown quantity of gas at a pressure of 204.83 kPa, a volume of 27.88 liters, and a temperature of 8.76°C , how ma

ny moles of gas do I have?​
Chemistry
2 answers:
Amiraneli [1.4K]2 years ago
8 0
Um what this answer is but I think 1.26
weeeeeb [17]2 years ago
6 0

Answer:

700

Explanation:

<u>How to find</u>

Multiply the volume and pressure and divide the product by the temperature and the molar gas constant to calculate the moles of the hydrogen gas.

Solve: 204.83 × 27.88 / 8.76 = 651.901872146

Which is 651.90

In the nearest hundredths, the moles of gas is 700

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A asystem at equilibrium stops
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Which of the following bases is the STRONGEST? The base is followed by its Kb.A. C6H5NH2, 4.0 × 10-10 B. NH3, 1.76 × 10-5 C. CH3
Kamila [148]

Answer:

(D) (CH3CH2)2NH

Explanation:

In order to decide which base is strongest we need to calculate its PKb

PKb = -log [Kb]

A large Kb value and small PKb value gives the strongest base

 Compound                   Kb                           PKb      

(A) C6H5NH2 -         4 x 10^-10                      9.349

(B) NH3                     1.76x 10^-5                    4.754

(C) CH3NH2              4.4x 10^-4                     3.357

(D) (CH3CH2)2NH   8.6x 10^-4                     3.066

(E) C5H5N                  1.7x10^-9                      8.77  

Clearly (CH3CH2)2NH is the strongest base.

3 0
3 years ago
Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00
Simora [160]

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

so

[OH^-]=10^(-pOH)

=10^-5

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4 0
3 years ago
The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti
OLEGan [10]

Answer:

m_{undissolved}=27g

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

m_{undissolved}=100g-73g\\\\m_{undissolved}=27g

Best regards!

3 0
2 years ago
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