Answer:
9. -4x+19y-7
10. 7x+20
Step-by-step explanation:
9. To simplify this expression, simply combine like terms. Add all of the terms with the x variable together, then the terms with the y variable, then the constant terms. I will show this step by step, but usually you do not have to show this work. The order of the terms does not matter.
x variable terms: (4x-8x)+7y-2+6y+6y-5= -4x+7y-2+6y+6y-5
y variable terms: (7y+6y+6y)-4x-2-5=19y-4x-2-5
constant terms: (-2-5)-4x+19y=-4x+19y-7
10. To simplify this expression, expand all terms and then combine like terms. The first term can be expanded by multiplying each term in the parentheses by 2.
Expand terms: 2(5+3x)+(x+10)= 10+6x+x+10
Now, you can combine like terms as done on the last problem. Note that I got rid of the parentheses in the second term, as they did not matter (since there was no term in front of them).
x variable terms: (6x+x)+10+10=7x+10+10
constant terms: (10+10)+7x=7x+20
The dimensions of the coop are length = 12 ft and width = 9 ft
<h3>Area of the coop</h3>
Since the coop is a rectangle, the area of the coop is A = LW where
- L = length of coop and
- W = width of coop.
Now, the length of the coop 3 feet longer than the width, so, L = W + 3
Now, the area of the coop A = 108 ft²
So, A = LW
A = (W + 3)W
108 = W² + 3W
Re-arranging,
W² + 3W - 108 = 0
So, we solve the equation to find the width of the coop
<h3>
Width of coop</h3>
W² + 3W - 108 = 0
Factorizing, we have
W² + 12W - 9W - 108 = 0
W(W + 12) - 9(W + 12) = 0
(W + 12)(W - 9) = 0
W + 12 = 0 or W - 9 = 0
W = -12 or W = 9
Since W cannot be negative, W = 9
<h3>
Length of coop</h3>
Since L = W + 3
Substituting the value of W into L, we have
L = W + 3
L = 9 + 3
L = 12 ft
So, dimensions of the coop are length = 12 ft and width = 9 ft
Learn more about dimensions of coop here:
brainly.com/question/15558785
Answer: Hello mate!
A fair die has the possible results of 1, 2, 3, 4, 5 and 6, where all have the same probability ( that is 1/6).
then when you throw the dice 12 times, all the possible arrays of 12 numbers between 1 and 6 have the same probability of showing up, that is equal to
(1/6)^12
this means that the distribution (iii) 6 6 6 6 6 6 6 6 6 6 6 6 (where each 6 has a 1/6 probability) has the same probabilities that (iv) 1 5 4 3 5 1 2 4 4 6 4 5 (where each number has the same probability; 1/6) and we here are imposing order, so the first number must be a 1, which has a 1/6, the second must be a 5, which also has a 1/6; this is the same for every number (doesn't matter if they are different or equal)
then the correct answer is: with a fair die. They are all equally likely.
Answer:
Es 60
Step-by-step explanation:
5/6 is the answer for your question
