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tiny-mole [99]
2 years ago
8

Expand and simplify (4x+1)(x+3)

Mathematics
2 answers:
Allisa [31]2 years ago
8 0
<span><span>(<span><span>4x</span>+1</span>)</span><span>(<span>x+3</span>)</span></span><span>
=<span><span>(<span><span>4x</span>+1</span>)</span><span>(<span>x+3</span>)</span></span></span><span>=<span><span><span><span><span>(<span>4x</span>)</span><span>(x)</span></span>+<span><span>(<span>4x</span>)</span><span>(3)</span></span></span>+<span><span>(1)</span><span>(x)</span></span></span>+<span><span>(1)</span><span>(3)</span></span></span></span><span>=<span><span><span><span>4<span>x2</span></span>+<span>12x</span></span>+x</span>+3</span></span><span>=<span><span><span>4<span>x2</span></span>+<span>13x</span></span>+<span>3</span></span></span>
kari74 [83]2 years ago
7 0
Answer is 4x^2+12x+1x+3 
  combine like term it will be
      4x^2+13x+3
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Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0   <em>This is not it!</em>

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0     <em>This is not it!</em>

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0     <em>This is it!</em>

Answer: C. x^2 + 2x - 1 = 3

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