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AveGali [126]
3 years ago
14

Please help!! I need the answer!!

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

The answer to your question is Area = 39.15 in²

Step-by-step explanation:

Data

See the picture below

Process

1.- Calculate the area of rectangle 1

Area = base x height

Area = (8.8)(6.55 - 4.3)

Area = (8.8)(2.25)

Area = 19.8 in²

2.- Calculate the area of rectangle 2

Area = (4.3)(2.25)

Area = 9.675 in²

3.- Calculate the area of rectangle 3

Area = (4.3)(2.25)

Area = 9.675 in²

4.- Calculate the total area

Area = 19.8 + 9.675 + 9.675

Area = 39.15 in²

Second way

Area 1 = 2[6.55 x 2.25]

Area 1 = 29.475 in²

Area 2 = (8.8 - 2.25 - 2.25)(6.55 - 4.3)

Area 2 = 4.3 x 2.25

Area 2 = 9.675 in²

Total area = 29.475 + 9.675

                 = 39.15 in²

Third way

Area 1 = (8.8 - 2.25)(6.55 - 4.3)

          = (6.55)(2.25)

          = 14.7375 in²

Area 2 = (4.3)(2.25)

           = 9.675 in²

Area 3 = (6.55)(2.25)

           = 14.7375 in²

Total area = 14.7375 + 9.675 + 14.7375

                 = 39.15 in²

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3 years ago
If x-5/4 = -9/5, then x =
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Answer:

[See Below]

Step-by-step explanation:

✦ First change the improper fractions to decimals:

  ✧ ⁵⁄₄ = 1.25

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✦ Then divide:

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So x would be -0.69 in decimal form.

~<em>Hope this helps Mate. If you need anything feel free to message me.</em>

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3 years ago
A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu
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Answer:

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Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= \frac{3}{4}×\frac{3}{4}

=\frac{9}{16}

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- \frac{9}{16}

=\frac{7}{16}

Second way:

Probability that first card drawn is a heart and the second one is not a heart= \frac{1}{4}×\frac{3}{4}

=\frac{3}{16}

Probability that the first card drawn is not a heart and the second one is a heart= \frac{3}{4}×\frac{1}{4}

=\frac{3}{16}

Probability that both cards drawn are hearts= \frac{1}{4}×\frac{1}{4}

=\frac{1}{16}

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= \frac{7}{16}


3 0
3 years ago
Factorize<br>8x²+10x-12 = ???<br><br>Juste tell me if(4x-3) (x+2) is the right answer please.
MrMuchimi
No it is wrong
the product of it is
4x²+5x-6
so you have to multiply by 2
the naswer is 2(4x-3)(x+2)
4 0
2 years ago
What is -4 3/8 - -1 1/4
Likurg_2 [28]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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