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AveGali [126]
3 years ago
14

Please help!! I need the answer!!

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

The answer to your question is Area = 39.15 in²

Step-by-step explanation:

Data

See the picture below

Process

1.- Calculate the area of rectangle 1

Area = base x height

Area = (8.8)(6.55 - 4.3)

Area = (8.8)(2.25)

Area = 19.8 in²

2.- Calculate the area of rectangle 2

Area = (4.3)(2.25)

Area = 9.675 in²

3.- Calculate the area of rectangle 3

Area = (4.3)(2.25)

Area = 9.675 in²

4.- Calculate the total area

Area = 19.8 + 9.675 + 9.675

Area = 39.15 in²

Second way

Area 1 = 2[6.55 x 2.25]

Area 1 = 29.475 in²

Area 2 = (8.8 - 2.25 - 2.25)(6.55 - 4.3)

Area 2 = 4.3 x 2.25

Area 2 = 9.675 in²

Total area = 29.475 + 9.675

                 = 39.15 in²

Third way

Area 1 = (8.8 - 2.25)(6.55 - 4.3)

          = (6.55)(2.25)

          = 14.7375 in²

Area 2 = (4.3)(2.25)

           = 9.675 in²

Area 3 = (6.55)(2.25)

           = 14.7375 in²

Total area = 14.7375 + 9.675 + 14.7375

                 = 39.15 in²

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How many moles of H2 would be required to produce 9.0 grams of water? 10<br> 2 H2 + O2 + 2 H20
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8.1 moles

Step-by-step explanation:

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6 0
3 years ago
75. Simplify the expression: -2x(4x^2 - 5x + 3)
Karolina [17]

-2x(4x² - 5x + 3)    Distribute/multiply -2x into (4x² - 5x + 3)

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Answer:

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Step-by-step explanation:

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2. The factors of 8 are 1, 2, 4, and 8. Out of these, 1, 2, and 4 are the only factors that 20 shares with it and 4 is the greatest. Then, we look at the K's and the GCF of the K's is k^7 since k^8 has seven K's. We multiply the two and we get 4k^7.

3. Since one of the numbers of the three given here does not include the variable n, there will not be any N's in the GCF of the three, so we don't have to worry about that. Now, we just find the GCF of 18, -24, and -21. The factors of 18 are 1, 2, 3, 6, 9, and 18, the factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24, and lastly, the factors of 21 are 1, 3, 7, and 21. From these, 3 is the biggest common divisor, therefore the GCF is 3.

4. Between the two X's, X^1 is the biggest amount of X's this GCF has, so the final GCF will be some constant multiplies with X. Since we are dealing with bigger numbers on this problem, we should use prime factorization. The prime factorization of 90 is 2 x 3 x 3 x 5, and the prime factorization of 120 is 2 x 2 x 2 x 3 x 5. From these expressions, we take the biggest amount of each common factor as we can. Since these expressions both have 2, we take the smaller amount of 2's which is one two. Then we get one three from both expressions, and one five as well. 2 times 3 times 5 equals 30, therefore, we get -30x, and not 30x, because both of these numbers are negatives.

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