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3 years ago

NEED HELP ASAP RIGHT NOW

Mathematics

1 answer:

g100num [7]3 years ago

6 0

Answer:

y=4x+40

Step-by-step explanation:

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Tyler solved an inequality to determine the number of songs he can buy with a $20 credit at his favorite music website. The solu

Furkat [3]

Answer with explanation:

Amount that tyler had for buying number of songs from his favorite music website=$ 20

A number line is given which describe the possible quantities of songs that Tyler can buy.

1. No more than 8 songs

4.at most 8 songs

6.a maximum of 8 songs

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3 years ago

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Write the point-slope form of the equation of the line through the given point with the given slope. (-5,0) slope= 2/3

amid [387]

Answer:

Step-by-step explanation:

y - 0 = 2/3(x + 5)

y = 2/3x + 10/3

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3 years ago

A chemist is mixing two solutions, solution A and solution B Solution A is 15% water and solution Bis 20% water. She already has

slavikrds [6]

Answer:

15 mL of the solution with 20% water will be needed.

Step-by-step explanation:

Use the inverse relationship

10 mL * (18-15)% = x mL * (20-18)%

x = 10 mL * (3/2) = 15 mL

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3 years ago

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$