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Mrrafil [7]
3 years ago
12

Is the equation below a function? explaind) y2 = x2 + 5​

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

No

Step-by-step explanation:

y^2 = x^2 + 5​

Rewriting

y^2 - x^2 = 5

This is a hyperbola

We can use the vertical line test to show that it is not a function since a vertical line passes through more than one point.

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Can somebody help me with these to questions how do you find the area of the circle
Grace [21]

13)

Circumference (C) = 2π·r

11π = 2π·r

11/2 = r

******************************

Area (A) = π·r²

             =  π·(11/2)²  

            = 121π/4

           ≈ 94.985 in²

14)

diameter = 2r

          42 = 2r

           21 = r

*******************

Area (A) = π·r²

             =  π·(21)²  

            = 441π

           ≈ 1384.74 in²

***************************

$280/1384.74 in²

x = $0.20

Answer: about 20 cents per square inch

 



                     

6 0
3 years ago
Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360
Natasha2012 [34]

\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]

\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

   \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]

5 0
3 years ago
Look at the image for the question
saw5 [17]
It’s 16
You would multiply height (4) by the base (length(2) x width(2)=4) which is 16
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3 years ago
Fernando puts 3 pictures on each page of his photo album. He puts pictures on 8 pages. Represent it by array.
lakkis [162]
X X X X X X X X
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6 0
3 years ago
Read 2 more answers
What's the estimate of 8 2/3 + 4 7/9. I really need help on this one.
VMariaS [17]

Answer:

13 4/9

Step-by-step explanation:

3 0
3 years ago
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