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Leni [432]
3 years ago
5

I want to know the answer of all of them

Mathematics
1 answer:
Nady [450]3 years ago
5 0
A. 3/5 * 60 minutes = 180/5 = 36 minutes
b. (3/4)/12 = 3/(4*12) = 3/48 = 1/16 cup
c. (5 1/3) / (2/3) = (16/3) / (2/3) = 16/3 * 3/2 = 48/6 = 8 days
d. 137/16 = 8.5625 pounds
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What’s the answer to 5-y=18
Scorpion4ik [409]

Answer:

y=-13

Step-by-step explanation:

5-y=18

-5    -5

-y=13

*-1   *-1

y=-13

5 0
3 years ago
At a local company, 15% of the employees are women. every day, 9% of them bring their lunch to work, while only 3% of the men br
fenix001 [56]

Answer:

a) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

b) 0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

c) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Questions a/c:

Questions a and c are the same, so:

Event A: Brings lunch to work.

Event B: Is a woman.

Probability of a person bringing lunch to work:

9% of 15%(woman)

3% of 100 - 15 = 85%(man). So

P(A) = 0.09*0.15 + 0.03*0.85 = 0.039

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.039} = 0.3462

0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Question b:

Event A: Woman

Event B: Brings lunch

15% of the employees are women.

This means that P(A) = 0.15

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.15} = 0.09

0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

4 0
2 years ago
Find the measure of &lt;2!<br> Answer fast pls, 15 pts! &lt;3
Gala2k [10]

Answer:

65

Step-by-step explanation:

180-115=65

It needs to be a total of 180 so just do what I did :)

6 0
3 years ago
Read 2 more answers
Can anyone answer this pls!!!!!!!!!!
gizmo_the_mogwai [7]

u₁₂ represents the amount of loan remaining after 12 years

<h3>How to interpret u₁₂?</h3>

The function is given as:

u₀ = 8000

u_n = u_{n-1}(1 + 0.054) - 500

Given that the subscript n in u_n represents number of years and u_n represents the amount left to be paid after n years.

We can conclude that:

u₁₂ represents the amount of loan remaining after 12 years

Read more about loan at
brainly.com/question/26011426

#SPJ1

6 0
2 years ago
What is the domain of f(x) = 3√x? all real numbers positive numbers and zero all integers whole numbers
N76 [4]

Answer:

  • B. positive numbers and zero

Step-by-step explanation:

<u>This is a square root function:</u>

  • f(x) = 3√x

The domain is the x-values which include all non-negative real numbers

Correct choice is B

4 0
2 years ago
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