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guajiro [1.7K]
3 years ago
14

A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters,

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0
You answer would be 80 cm^2
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3 years ago
Xavier needs to bike a minimum of 80 miles this week for his training. If he already biked 14 miles this week, then how many mil
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3 years ago
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vredina [299]

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14cm (i think)

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3 0
2 years ago
Urgent. Please show all work
myrzilka [38]

Answer:

\displaystyle f'(x) = \frac{4}{x^2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Limit Rule [Variable Direct Substitution]:                                                    \displaystyle \lim_{x \to c} x = c

Differentiation

  • Derivatives
  • Derivative Notation

The definition of a derivative is the slope of the tangent line:                             \displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em />\displaystyle f(x) = -\frac{4}{x}

<u>Step 2: Differentiate</u>

  1. [Function] Substitute in <em>x</em>:                                                                            \displaystyle f(x + h) = -\frac{4}{x + h}
  2. Substitute in functions [Definition of a Derivative]:                                   \displaystyle f'(x) = \lim_{h \to 0} \frac{-\frac{4}{x + h} - \big( -\frac{4}{x} \big)}{h}
  3. Simplify:                                                                                                        \displaystyle f'(x) = \lim_{h \to 0} \frac{4}{x(x+ h)}
  4. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle f'(x) = \frac{4}{x(x+ 0)}
  5. Simplify:                                                                                                        \displaystyle f'(x) = \frac{4}{x^2}

∴ the derivative of the given function will be equal to 4 divided by x².

---

Learn more about derivatives: brainly.com/question/25804880

Learn more about calculus: brainly.com/question/23558817

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0
2 years ago
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