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2 years ago

74.64 rounded to the nearest tenth how do you round a decimaled number?

Mathematics

1 answer:

Irina18 [472]2 years ago

5 0

Answer:

$\displaystyle 74,6$

Step-by-step explanation:

You have a 6 in the tenths position, so the 4 in the hundredths position tells you to STAY at $\displaystyle 74,6.$

I am joyous to assist you at any time.

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Point R is located at (3, 2) and point S is located at (8, 15) . What are the coordinates of the point that partitions the direc

Sliva [168]

Hello There!

The coordinates would be (17/4, 21/4)

Hope This Helps You!
Good Luck :)

- Hannah ❤

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4 years ago

Represent the arithmetic series using the recursive formula 94, 87, 80, 73,

Rama09 [41]

Answer:

$a_1 = 94 \\ a_n = a_ {n - 1} - 7$

Step-by-step explanation:

The given arithmetic sequence is 94, 87, 80, 73,...

The first term is

$a_1=94$

The common difference is

$d = 87 - 94$

$d = - 7$

The recursive formula is given by:

$a_n = a_ {n - 1} + d$

We substitute the common difference to obtain:

$a_n = a_ {n - 1} - 7$

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3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

Write an equation for the line that passes through (-2,4) and (0,7)

xz_007 [3.2K]

Answer:

y = 3/2x + 7

Step-by-step explanation:

The slops is rise over run, so in this case the slope is 3/2 because it goes up 3 units while going 2 units to the right.

The points (0,7) is on the y axis. This means that 7 is the y intercept

With this information, we can follow the format of the slope intercept equation: y = mx + b

m stands for the slope and b stands for the y intercept. Plugging the information in, our equation is:

y = 3/2x + 7

8 0

3 years ago

What is the domain and range of f(x)= |x-6|

marissa [1.9K]

Domain: possible x values
Range: possible y values

Solution: domain: all real numbers
Range: y greater than 0

7 0

3 years ago