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Mumz [18]
3 years ago
9

The area of the regular octagon is approximately 54 cm2. What is the length of line segment AB, rounded to the nearest tenth?

Mathematics
2 answers:
spayn [35]3 years ago
8 0

Answer:3.4

Step-by-step explanation:

For enginuity- just took the test

erastova [34]3 years ago
6 0

Answer:

AB = 3.3 cm

Step-by-step explanation:

The formula to find out area of a regular octagon is given by

A=2(1+\sqrt{2})a^{2}

where a is the length of each side of the regular octagon.

Plugin A=54 into the formula

54=2(1+\sqrt{2})a^{2}

Divide both sides by 2

\frac{54}{2} =\frac{2}{2} (1+\sqrt{2})a^{2}

27 = (1+\sqrt{2})a^{2}

Plugin √2 as 1.41

27 = (1+1.41)a^{2}

27 = (2.41)a^{2}

Divide both sides by 2.41

\frac{27}{2.41} = \frac{2.41}{2.41} a^{2}

11.20 = a^{2}

Taking square root on both sides

\sqrt{11.20}  = \sqrt{a^{2}}

a = 3.346

a = 3.3 cm (rounded to nearest tenth)

so, length of side AB = 3.3 cm

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