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3 years ago

The area of the regular octagon is approximately 54 cm2. What is the length of line segment AB, rounded to the nearest tenth?

Mathematics

2 answers:

spayn [35]3 years ago

8 0

Answer:3.4

Step-by-step explanation:

For enginuity- just took the test

erastova [34]3 years ago

6 0

Answer:

AB = 3.3 cm

Step-by-step explanation:

The formula to find out area of a regular octagon is given by

$A=2(1+\sqrt{2})a^{2}$

where a is the length of each side of the regular octagon.

Plugin A=54 into the formula

$54=2(1+\sqrt{2})a^{2}$

Divide both sides by 2

$\frac{54}{2} =\frac{2}{2} (1+\sqrt{2})a^{2}$

$27 = (1+\sqrt{2})a^{2}$

Plugin √2 as 1.41

$27 = (1+1.41)a^{2}$

$27 = (2.41)a^{2}$

Divide both sides by 2.41

$\frac{27}{2.41} = \frac{2.41}{2.41} a^{2}$

$11.20 = a^{2}$

Taking square root on both sides

$\sqrt{11.20} = \sqrt{a^{2}}$

a = 3.346

a = 3.3 cm (rounded to nearest tenth)

so, length of side AB = 3.3 cm

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The sum of 9and -16 increased by 4

LenaWriter [7]

Answer:

-3

Step-by-step explanation:

The statement is,

→ Sum of 9 and -16 increased by 4

The equation will be,

→ {9 +(-16)} + 4

→ (9 - 16) + 4

→ -7 + 4

→ [ -3 ]

Hence, the solution is -3.

7 0

2 years ago

Find the distance between (5, 3) and (1, 3).

Dafna11 [192]

Answer: 4 units

Step-by-step explanation:

(5-1,3-3)=(4,0)==> 4 units

7 0

2 years ago

I really need help with this one please help

Dominik [7]

Yo sup??

a.For this part just draw a triangle with sides 4,8 and 8 inches respectively.

The sides having 8 inches should make equal angle with the base side.

b.One angle is 20

The other two angles be x and y

but x=y because its an isosceles triangle

x+y+20=180

2x=160

x=80

Hope this helps.

5 0

3 years ago

Select the correct answer from each drop-down menu.

olganol [36]

The system of inequalities is:

y ≤ -0.05*x^2 + 6x

y > 1.5x + 45

(30, 90) is not a solution of that system, while (60, 160) is a solution.

<h3>How to get the system of inequalities?</h3>

We know that the revenue y is given by:

y ≤ -0.05x^2 + 6x

And we know that the costs are 1.5x + 45, and the revenue must be larger than that, so we also have the inequality:

y > 1.5x + 45

So the system is:

y ≤ -0.05*x^2 + 6x

y > 1.5x + 45

Now, the point (30, 90) means that we need to replace x by 30 and y by 90, replacing that in the second inequality, we will get:

90 > 1.5*30 + 45 = 90

90 > 90

This is false, so the point is not a solution of this inequality, meaning that the point is not a solution of the system.

For the second point we do the same: x= 60, y = 160, replacing that in the second inequality we get:

160 > 1.5*60 + 45 = 135

160 > 135

This is true, now we need to check with the other inequality.

160 ≤ -0.05*60^2 + 6*60 = 180

This is also true.

So the point (60, 160) is a solution to the system.

If you want to learn more about systems of inequalities, you can read:

brainly.com/question/9774970

8 0

2 years ago

Read 2 more answers

A factory sells backpacks for $40.00 each. The cost to make 1 backpack is $10.00. In addition to the cost of making backpacks, t

Angelina_Jolie [31]

Answer:

<h2>The factory needs to sell 327 packbacks to make at least 9,800 per week.</h2>

Step-by-step explanation:

We know that each backpacks is sold for $40.00.

The goal is to make at least $9,800 per week. With this information we can define the inequality

$40x -10x \leq 9,800$

Where $x$ represents backpacks. Notice that this inequality is about profits, that's why we subtract the cost from the sell price, in this case, the profid margin is $30.00 per backpack, so

$30x\leq 9,800$

Solving for $x$

$x\leq \frac{9800}{30}\\ x \leq 326.67$

Therefore, the factory needs to sell 327 packbacks to make at least 9,800 per week.

7 0

3 years ago