Answer:
(x−2)2+(y+1)2=100
Explanation:
the standard form of the equation of a circle is
2
2
(
x
−
a
)
2
+
(
y
−
b
)
2
=
r
2
2
2 where (
a
,
b
) are the coordinates of the center and r is the radius to find the center we require the midpoint of the 2 given points center =
[
1
2
(
−
4+
8
)
,
1
2
(
7
−
9
)
] center
=
(
2
,
−
1
) the radius is the distance from the center to either of the 2 given points calculate the radius using the distance formula
∙ d
=
√
(
x2
−
x
1
)
2
+
(
y
2
−
y
1
)
2 let (
x
1
,
y
1)
=
(
2
,
-1
) and (
x
2
,
y
2
)
=
(
−
4
,
7
)
r
=
√
=
√
(
−
4
−
2
)
2
+
(
7
+
1
)
2
=
√
36
+
64
=
10
⇒
(
x
−
2
)
2
+
(
y
−
(
−
1
)
)
2
=
10
2
⇒
(
x
−
2
)2
+
(
y
+
1
)
2
=
100
← equation of circle
The statement b is true. A function is increasing when the slope of the tangent is positive. Between 2 and 3, the function has a positive slope so it is increasing.
Well, 7*3= 21 so all you have to do is add the zeros to get: 210,000
:)
Hope this helped!
I think the answer would be -2.5 because 0-5=-5 and 4-2=2 you subtract the perfect points X1-x2 with y2-y1
If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
