There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,
2 answers:
Answer:
The answer is 79%
Step-by-step explanation:
First we will write the numbers in order.
72, 74, 76, 78, 80, 82, 92, 92
When the given set of values have odd number of items, the median is the center number.
But here the data set is even,so we will find the average of the two center numbers, that are 78 and 80.
The average becomes:
Therefore, the answer is 79%
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Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error of the interval is given by:
In this problem, we have that:
99.5% confidence level
So , z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Answer:
5859375
Step-by-step explanation:
These are the terms of a geometric sequence with n th term
=
where r is the common ratio and the first term
here r = =
=
= 5 and
= 3, hence
= 3 ×
= 5859375