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Delicious77 [7]
4 years ago
12

I am even. The sum of my digits is sixteen. Who am I?

Mathematics
1 answer:
Tju [1.3M]4 years ago
7 0

Answer:

2, 4, 6, 8, 10, 12, 14

Step-by-step explanation:

8+8=16

6+10=16

4+12=16

2+14=16

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I will mark you
Nana76 [90]

Answer:

Yes, because the x's do not have more than one y.

Step-by-step explanation:

x      y

0      0

5       10

6       12

10     20

(That's meant to be a table). Looking at the x and y table values, you can see that none of the x's have two y's. So, this relation is a function.

7 0
3 years ago
3(x-5)+4=4-2(x-1) <br><br>worked it out just need to see if answers right
Gennadij [26K]
Cleared the P's first, then muilt by 4 to clear the "D" and last solved for X and got 4.2

5 0
3 years ago
Read 2 more answers
Help? Please? Mathematics isn't my thing.
Natali5045456 [20]
C is the correct answer. The equation for f(x) is f(x)=1.8x-10 and the equation for g(x) is g(x)=-4 . Since we're trying to find the input value for x where f(x)=g(x) make the 2 equations equal to each other and you'll get your answer.
4 0
4 years ago
Simplify completely (x^2-15x+36)/(5x-60)
zalisa [80]

Answer:

x-3/5

Step-by-step explanation:

Im pretty sure this is the answer but i really hope it is.


5 0
3 years ago
Find the distance between the points G(-5, 4) and H(2, 6).
vladimir2022 [97]

Answer:

The answer is

<h2>\sqrt{53}  \:  \: or \:  \: 7.28 \:  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

G(-5, 4) and H(2, 6)

The distance between them is

|GH |  =  \sqrt{ ({ - 5 - 2})^{2}  +  ({4 - 6})^{2} }  \\  =  \sqrt{ ({ - 7})^{2} + ( { - 2})^{2}  }  \:  \\  =  \sqrt{49 + 4}   \\  =  \sqrt{53}  \:  \:  \:  \:  \:  \:  \:  \:   \\  = 7.280109

We have the final answer as

\sqrt{53}  \:  \: or \:  \: 7.28 \:  \:  \:  \: units

Hope this helps you

4 0
3 years ago
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