Let
be the weight of i-th player.
1. If the mean weight of 4 backfield members on the football team is 221 lb, then

2. If the mean weight of the 7 other players is 202 lb, then

3. From the previous statements you have that

Add these two equalities and then divide by 11:

Answer: the mean weight of the 11-person team is 
Answer:
c=7
Step-by-step explanation:
How to solve your problem
8=−3+29
8=−3c+298=-3c+298=−3c+29
Solve
1
Subtract
29
292929
from both sides of the equation
8=−3+29
8=−3c+298=-3c+298=−3c+29
8−29=−3+29−29
8−29=−3c+29−298{\color{#c92786}{-29}}=-3c+29{\color{#c92786}{-29}}8−29=−3c+29−29
2
Simplify
3
Divide both sides of the equation by the same term
4
Simplify
Solution
=7
Hope this helps!
Have a great day!
-Lea
1 quarter = 0.25
2 dimes = 2(0.10) = 0.20
2 nickels = 2(0.05) = 0.10
for a total of : 0.25 + 0.20 + 0.10 = 0.55.....so u have lost 0.55
I would say to the 5th degree because that's the highest exponent there but not 100% sure but I'm pretty sure
Sorry I can't help you more but I hope this helps ome