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stiv31 [10]
3 years ago
14

Find the volume of the pyramid below.

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer: 400 units

Step-by-step explanation:

Volume=1/3a^2h

=1/3(10)^2(12)

=400

denis23 [38]3 years ago
5 0

The correct answer is 400. I had the same question on a test I took not to long ago.

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A milkshake recipe calls for 1/3 cup of milk for each milkshake. If a server has 15/8 cups of milk, what is the maximum number o
Zepler [3.9K]

Answer:

5 milk shakes

Step-by-step explanation:

From the above question, we know that for the recipe

1/3 cup of milk = 1 milk shake

15/8 cup of milk = y milk shakes

We cross Multiply

15/8 cup × 1 = 1/3cup × y

y = 15/8 cup × 1 /1/3cup

= 15/8 ÷ 1/3

= 15/8 × 3

= 45/8

= 5.625 of 5 5/8 cups of milk

Therefore, the maximum number of

milkshakes the server can make following the recipe porpotians is 5 milk shakes.

4 0
3 years ago
If Ali wears a green shirt then we will take a test if we take a test then everyone will pass the test
tresset_1 [31]

Answer:

yea only ofc

Step-by-step explanation:

3 0
3 years ago
Solve each inequality. Justify each step (y-) - 4 + 2y > 11
Anna11 [10]
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
4 0
3 years ago
Choose the correct written expression for: (9 x 4) 6.
chubhunter [2.5K]

Answer:

D

Step-by-step explanation:

Product means to multiply 2 numbers and for this question its 9x4. The devided by 6 part is just divided from 6. so (9x4)/6

Hope this helped!

8 0
3 years ago
Read 2 more answers
The average weight of the entire batch of the boxes of cereal filled today was 20.5 ounces. A random sample of four boxes was se
zhenek [66]

Answer:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

Step-by-step explanation:

For this case we have the following dataset given:

20.05, 20.56, 20.72, and 20.43

We can assume that the distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for this case would be:

SE= \frac{\sigma}{\sqrt{n}}

And we can estimate the deviation with the sample deviation:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

4 0
3 years ago
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