Question

Help please!!! Thank you

Answer 1

Given:

The given expression is $\frac{4 d+28}{12 d+96} \cdot \frac{d^{2}+14 d+48}{d^{2}+9 d+14}$

We need to multiply the terms.

Multiplication of the terms:

Before multiplying the terms, first we shall find the factors of the quadratic equations.

Thus, we have;

$\frac{4 d+28}{12 d+96} \cdot \frac{(d+6)(d+8)}{(d+2)(d+7)}$

Factor out the common terms, we get;

$\frac{4 (d+7)}{12 (d+8)} \cdot \frac{(d+6)(d+8)}{(d+2)(d+7)}$

Let us cancel the common terms from the above expression.

Thus, we have;

$\frac{4 }{12 } \cdot \frac{(d+6)}{(d+2)}$

Simplifying, the term, we get;

$\frac{1}{3 } \cdot \frac{(d+6)}{(d+2)}$

Now, we shall multiply the terms.

Hence, multiplying the terms, we get;

$\frac{(d+6)}{3(d+2)}$

Thus, the multiplied value of the given expression is $\frac{(d+6)}{3(d+2)}$