To the nearest tenth, what is the area of the shaded segment when AG = 6 ft?
2 answers:
You might be interested in
Ax²+bx+c=0
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3
The formula to solve for x is:
So for 3x²+13x+10=0, plug in the data
x=-13±√13²-4(3)(10) / 2(3)
x=-13±√169-120 / 6
x=-13±√49 /6
x=-13<span>±7 / 6
x=-13+7/6
x=-6/6
x=-1
x=-13-7/ 6
x=-20/6 or 3.3repeating
3x</span>²+14x+15=0
x=-14±√14²-4(3)(15) / 2(3)
x=-14±√196-180 /6
x=-14<span>±</span>√16 / 6
x=-14+4/6
x=-10/6 or 1.6repeating
x=-14-4/6
x=-18/6
x=-3