Hello :
hello : <span>
1 ) if : x</span>ـــــــ> ± ∞
<span>
limf(x) = b ....(b</span>∈R) so : y=b is the equation of
the line horizontal asymptote.
<span>
2) if : x</span>ـــــــ>
a ...(a∈R)<span>
limf(x) = ± ∞
<span>so : x=a is the equation of the
line vertical asymptote.</span></span>
<span><span>hint : in this exercice : a = 2 or a = 7 but : b=2</span></span>
Answer:
C. 0.492
Step-by-step explanation:
All I did was add the two numbers. Add them like normal, even though they are in decimal form. You could also use a calculator. If you don't have one, there should be one programed into your phone and computer.
0.467
+ 0.025
= 0.492
I hope this helps! Please let me know if you have any more questions or need any more help. Have a great day!
We are trying to find the number that when added to 19, gives us less than 42. We can set up this simple inequality:
19 + x < 42
Now, subtract 19 from both sides:
x < 23
Our number can be anything less than 23.
Answer:
x= 2 and y = -4
Step-by-step explanation:
8x + 3y = 4 ---------------------------------(1)
-7x + 5y = -34 -----------------------------(2)
Multiply through equation (1) by 5 and multiply through equation(2) by 3
40x + 15y = 20 ----------------------------(3)
-21x + 15y =-102----------------------------(4)
Subtract equation (4) from equation (3)
61x = 122
Divide both-side of the equation by 61
61x/61 = 122/61
(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)
x = 122/61
x=2
Substitute x= 2 into equation (1)
8x + 3y = 4
8(2) + 3y = 4
16 + 3y = 4
Subtract 16 from both-side of the equation
16-16 + 3y = 4-16
3y = -12
Divide both-side of the equation by 3
3y/3 = -12/3
y = -4
x= 2 and y = -4
