OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
Answer:
StartFraction negative 1 Over k cubed EndFraction
Step-by-step explanation:
3k / (k + 1) × (k²- 1) / 3k³
= 3k(k² - 1) / (k + 1)(3k³)
= 3k³ - 3k / 3k⁴ + 3k³
= -3k / 3k⁴
= -1/k³
StartFraction k + 1 Over k squared EndFraction
(k + 1) / k²
StartFraction k minus 1 Over k squared EndFraction
(k - 1)/k²
StartFraction negative 1 Over k cubed EndFraction
= -1/k³
StartFraction 1 Over k EndFraction
= 1/k
Answer:
y intercept is -5 and slope is 6/1
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Given the following question:
In order to find the answer, we simply apply the exponent rule and add the exponents.
The answer is option B or "5^6."
Hope this helps.
Answer:
Step-by-step explanation:
From the given right angle triangle,
The unknown side represents the hypotenuse of the right angle triangle.
With m∠40 as the reference angle,
x represents the adjacent side of the right angle triangle.
4 represents the opposite side of the right angle triangle.
To determine x, we would apply
the Tangent trigonometric ratio.
Sin θ = opposite side/hypotenuse. Therefore,
Tan 40 = 4/x
x = 4/Tan 40 = 4/0.839
x = 4.8
