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skad [1K]
3 years ago
8

4. In your own words, describe what a treatment is in an experiment.

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Answer:

Step-by-step explanation:

In an experiment, the factor also known as independent variable is the variable that helps to explain something employed or utilized by the one carrying out an experiment. In every factor there are two or more different values of the factor, adopting different factor levels is knowns as treatment.

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natta225 [31]

Answer:

Step-by-step explanation:

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3 years ago
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Please need some help on this
vredina [299]
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8 0
3 years ago
A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of
Elis [28]

Answer:

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

\hat p=0.27 estimated proportion of arrests that were not prosecuted

p_o=0.31 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:  

Null hypothesis:p\geq 0.31  

Alternative hypothesis:p < 0.31  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

3 0
3 years ago
A survey of couples in a city found the following probabilities:
liraira [26]

Answer

(a) 0.94

(b)0.06

Step-by-step explanation:

P(husband is employed) = P(H) = 0.85

P(wife is employed) = P(W) = 0.59

P(both are employed) = P(H∩W) = 0.50

(a) At least one of them is employed

= P(H∪W)

= P(H) + P(W) - P(H∩W)

=0.85 + 0.59 - 0.50

=0.94

(b) Neither is employed,

=1 - P(H∪W)

= 1-0.94

=0.06

8 0
3 years ago
If f(x)=1/7-9, then f^-1(x)=
artcher [175]

Answer:

Step-by-step explanation:

Hello!

f(x)=\frac{1}{7} -9=\frac{1-9*7}{7} =-\frac{62}{7} \\=>f^{-1} (x)=-\frac{7}{62}\\

Good luck!

4 0
3 years ago
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