An exam is made of two papers that score differently.

Alma was given some money as a gift and deposited it into a savings account. She makes a withdrawal of the same amount at the en

Kryger [21]

Answer:

input= starting amount

output= withdrawals

(5,442) and (13,226)

Step-by-step explanation:

for input its what you put in the account for output its for what you take out.

And for the two points it the months first then you put how much money was left .

Hope this helps!

5 0

2 years ago

Find g(x), where g(x) is the reflection across the y-axis of f(x)=x.

3241004551 [841]

X➝-x by reflection, so g(x)=-x

7 0

2 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago

12x15y=4140; x+y= ? <br> solve.

Semenov [28]

Answer: The number of $12 tickets and $15 sold are 120 and 180 respectively.

Step-by-step explanation:

The given equation is:

12x + 15y = 4140 .....(1)

Where,

x stands for $12 tickets and y stands for $15 tickets

According to the question:

x + y = 300 ....(2)

Now solving equation 1 and 2.

From equation 2:

x = 300 - y

Now putting this expression in equation 1.

12x + 15y = 4140

12(300 - y) + 15y = 4140

3600 - 12y + 15y = 4140

3600 + 3y = 4140

3y = 4140 - 3600

3y = 540

y = 180

And,

x = 300 - y = 300 - 180 = 120

The number of $12 tickets sold = x = 120

The number of $15 tickets sold = y = 180

Thus, the number of $12 tickets and $15 sold are 120 and 180 respectively.

4 0

2 years ago

A linear function is written:<br> f(x) = 3/2x-4<br> What is the value of f(5)?

valentinak56 [21]

Answer:

$f(5)=3.5$

Step-by-step explanation:

$f(x)=\frac{3}{2}x-4\\f(5)=\frac{3}{2}(5)-4\\f(5)=7.5-4\\f(5)=3.5$

Hope this helped!! Have an amazing day :D

4 0

3 years ago