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alekssr [168]
3 years ago
10

Please help me :(

Mathematics
1 answer:
damaskus [11]3 years ago
3 0
You could use sine to find it
sin45 = 8/m
m = 8/sin45
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PLEASE HELP ILL MAKE YOU THE BRAINIEST What is the value of x
Alex787 [66]

~~~~~~\cos 45^{\circ}  = \dfrac{\text{Base}}{\text{Hypotenuse}}\\ \\\implies \dfrac 1{\sqrt 2} = \dfrac{x}{22}\\\\\implies x = \dfrac{22}{\sqrt 2}\\\\\implies x = \dfrac{22\sqrt 2}{2}\\\\\implies x = 11\sqrt 2\\

8 0
2 years ago
Read 2 more answers
Ignore this please, wanted to delete it but couldn't
konstantin123 [22]

Answer: ok

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ME!!!! 60 POINTS!!!
givi [52]

All of these equations will be set up as: h(t) = -\frac{g}{2}t^{2} +v₀t + h₀ where g represents gravity, v₀ represents initial velocity, and h₀ represents initial height. When working with ft/sec, g = 32. So, -g/2 = -16

1a) Length of time to reach its maximum height means you are looking for the x-value of the vertex (aka Axis Of Symmetry).

h(t) = -16t² + 160t

AOS: x = \frac{-b}{2a} = \frac{-160}{2(-16)} = 5

Answer: 5 sec

1b)  Length of time to fall to the ground means you are looking for the x-intercept when height (y-value) = 0.

h(t) = -16t² + 160t

0 = -16t² + 160t

0 = -16t(t - 10)

0 = -16t        0 = t - 10

t = 0               t = 10

t = 0 is when it started, t = 10 is when fell to the ground.

Answer: 10 sec

2c) Same concept as 1a

h(t) = -16t² + 288t

AOS: x = \frac{-b}{2a} = \frac{-288}{2(-16)} = 9

Answer: 9 sec

2d) Same concept as 1b

h(t) = -16t² + 288t

0 = -16t² + 288t

0 = -16t(t - 18)

0 = -16t         0 = t - 18

t = 0              t = 18

Answer: 18 sec

3e) Same concept as 1a

h(t) = -16t² + 352t

AOS: x = \frac{-b}{2a} = \frac{-352}{2(-16)} = 11

Answer: 11 sec

3f) Same concept as 1b

h(t) = -16t² + 352t

0 = -16t² + 352t

0 = -16t(t - 22)

0 = -16t         0 = t - 22

t = 0              t = 22

Answer: 22 sec

4 0
3 years ago
Read 2 more answers
Element X is a radioactive isotope such that its mass decreases by 59% every day. If an experiment starts out with 390 grams of
miss Akunina [59]

Answer:

The function that represents the mass of the sample after t days is A(t) = 390(0.41)^t.

The percentage rate of change per hour is of -2.46%.

Step-by-step explanation:

Exponential amount of decay:

The exponential amount of decay for an amount of a substance after t days is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount, and r is the decay rate, as a decimal.

Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.

This means, respectively, that r = 0.59, A(0) = 390

So

A(t) = A(0)(1-r)^t

A(t) = 390(1-0.59)^t

A(t) = 390(0.41)^t

The function that represents the mass of the sample after t days is A(t) = 390(0.41)^t.

Hourly rate of change:

Decreases by 59% every day, which means that for 24 hours, the rate of change is of -59%. So

-59%/24 = -2.46%

The percentage rate of change per hour is of -2.46%.

5 0
3 years ago
Could someone please check this Math Problem, Thank you.
Nikitich [7]
It looks right! Good job!
7 0
3 years ago
Read 2 more answers
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