Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
The correct answer should 4% because the ratio is 3 out of 75 which would leave 72 non-defective bulbs. So your answer is 4%
9514 1404 393
Answer:
102
Step-by-step explanation:
The total of ratio units is ...
6 + 3 + 8 = 17
The difference between the Charlie's ratio units and Adrian's ratio units is ...
8 - 6 = 2
That is, the total number of ratio units is 17/2 = 8.5 times that difference.
The actual difference is 12 sweets, so the total number of sweets is ...
8.5 × 12 = 102 . . . . total sweets
Answer:
2.1%
Step-by-step explanation:
The answer would be B) all the powers have the value of 1 because the exponent is zero
