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AfilCa [17]
3 years ago
8

In 1 hr, a plane can travel 390 mi into the wind and 470 mi with the wind. Find the wind speed and the rate of the plane in stil

l air.
The wind speed is mph.
The rate of the plane in still air
mph
Mathematics
1 answer:
Komok [63]3 years ago
7 0

Let <em>w</em> be the wind speed and <em>p</em> the plane's speed in still air.

Flying against the wind, the plane has velocity

<em>p</em> - <em>w</em> = 390 mi/h

and flying with it, it has

<em>p</em> + <em>w</em> = 470 mi/h

Add the two equations together to eliminate <em>w</em> and solve for <em>p</em> :

(<em>p</em> - <em>w</em>) + (<em>p</em> + <em>w</em>) = 390 mi/h + 470 mi/h

2<em>p</em> = 860 mi/h

<em>p</em> = 430 mi/h

Subtract them to eliminate <em>p</em> and solve for <em>w</em> :

(<em>p</em> - <em>w</em>) - (<em>p</em> + <em>w</em>) = 390 mi/h - 470 mi/h

-2<em>w</em> = -80 mi/h

<em>w</em> = 40 mi/h

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7 0
3 years ago
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

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