Round 496.042 to the nearest hundredth. Enter your answer in the response box. HElppp

BUILDING A horse farm is developing a new indoor arena in a rectangular building. They want the width of the building to be 3y f

MakcuM [25]

Answer:

3y(4y+9)=12y^2+27y......

6 0

2 years ago

Write the equation of this circle in standard form. please give answer?

Law Incorporation [45]

Given the center $(x_0,y_0)$ and the radius $r$ of a circle, its equation is

$(x-x_0)^2+(y-y_0)^2=r^2$

In your case, the center is (-4,0), and the radius is 2. Plug these values into the generic formula and you'll get the equation.

3 0

3 years ago

Which statement is correct when a scatterplot is constructed? A.The independent variable is the input variable and should be rep

spayn [35]

Answer:- A.The independent variable is the input variable and should be represented by the x-axis.

Explanation:-

A. Correct.

B. Not correct.

Reason:- The independent variable is the input variable and should be represented by the x-axis.

C. Not correct.

Reason:- The dependent variable is the output variable and should be represented by y-axis.

D. Not correct.

Reason:-The dependent variable is the output variable and should be represented by y-axis.

6 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

9/3 divided by 1/7 Someone pls help

irinina [24]

Answer:

the answer is 9/21

simplified is 3/7

7 0

3 years ago