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3 years ago

Triangle PQR is a right triangle.

Mathematics

2 answers:

jonny [76]3 years ago

6 0

Answer:

90 + 2 = 92

180 - 92 = 88

Angle Q = 88

Step-by-step explanation:

All a triangles, angles should equal to 180.

Ulleksa [173]3 years ago

6 0

Answer:

180 = 3 x + 90

Step-by-step explanation:

Hope it helps.Give me a brainliest please.

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What is the slope of the line in the graph?

Viktor [21]

Answer:

The slope of the line in the graph is 1.

Step-by-step explanation:

Slope is determined by rise over run. Meaning that the number of units the slope goes up/down divided by the number of units the slope goes to the left/right is the slope. The rise is one, and the run is one. 1 over 1 equals 1.

4 0

3 years ago

Read 2 more answers

7. In a quiz bee, Marlon scored 132 points during the first round. This score was thrice as much as his score during the second

podryga [215]

Answer:

II + III = 176

II = 44

III = 132

Step-by-step explanation:

Third round: 132

Second round: 3x=132

x=44 (second round)

2rounds: 132+44=176

4 0

2 years ago

there are 120 seats in the balcony of theatre .if this 1/5 of the total seats, what's the total number of seats in the theater

natka813 [3]

Answer:

600 seats

Step-by-step explanation:

We know there is 120 seats on a balcony and that is $\frac{1}{5}$ of the total seats, we want to find the total number of seats so,

120 seats = $\frac{1}{5}$

We know that a whole fraction sums to 1 so for example $\frac{1}{5} +\frac{4}{5} =\frac{5}{5} =1$

120 seats = $\frac{1}{5}$

Multiply both sides to make it a whole fraction

600 seats = $\frac{5}{5} =1$

So if there is 120 seats and that number is only $\frac{1}{5}$ of the total number of seats then the total number of seats is 600

3 0

3 years ago

Read 2 more answers

A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo

klemol [59]

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$ megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence, number of words can be stored = $4.3\times10^7$

4 0

3 years ago

Pls help me I don’t know what to do

aleksandrvk [35]

On what do u Need help on?

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3 years ago